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hp placement paper – 3

HP PLACEMENT PAPER – 3

PART- 1 –> 40 q’s (Fundamental computer Concepts, includes OS,N/w , protocols)

PART-2 –> 20 q’s (Purely C )

PART-3 –> 20 q’s (Analytical)

Q : What is not a part of OS ?

O : swapper,compiler,device driver,file system.

A : compiler.

Q : what is the condition called when the CPU is busy swapping in and out pages of

memory without doing any useful work ?

O : Dining philosopher’s problem,thrashing,racearound,option d

A: thrashing.

Q : How are the pages got into main memory from secondary memory?

DMA, Interrupts,option3, option 4

A : as far as i know its Interrupts –by raising a page fault exception.

Q : What is the use of Indexing ?

O : fast linear access, fast random access, sorting of records , option 4

A : find out….

Q : in terms of both space and time which sorting is effecient.(The question is

rephrased .)

O : merge sort, bubble sort, quick sort, option 4

A : find out

which case statement will be executed in the following code ?

main()

{ int i =1; switch(i)

{ i++; case 1 : printf (“”); break;

ase 2 : printf(“”); break;efault : printf(“”); break;

Answer : Case1 will only be executed.

Q : In the given structure how do you initialize the day feild?

struct time {

char * day ;

int * mon ;

int * year ;

} * times;

Options : *(times).day, *(times->day), *times->*day.

Answer : *(times->day) — after the execution of this statement compiler generates

error.i didn’t understand why.can anybody explain.

Q: The char has 1 byte boundary , short has 2 byte boundary, int has 4 byte boundary.

what is the total no: of bytes consumed by the following structure:

struct st {char a ; char b; short c ; int z[2] ; char d ; short f; int q ;

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